Page 3 of 3 
[ 40 posts ] 
Trying to look into the economics of SpaceX
Author  Message 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Before correcting and improving the equation system to incoprporate the
time structure all factors were applied to the same value of the labour costs L. That value is L2006 now.And as can be seen by the values got for L2007 and L2008 there is growth of L now. This means that g, h and j have to be applied to higher values than i and g and ha to a higher value than j. What about the effect on the launch operations team? In principle the number of rockets is growing â€“ this may be a reason to assume that the launch operations team should grow also. On the other hand the number of launches will be of meaning for the growth of the launch operations team â€“ and the number of launches per Quartal seems to be constant to a very large degree. Peaks might be handeled via temporaryly moving employees from the R&Dteam to the launch operations team for example. From my point of view the table I posted based on the launch manifestversions Klaus posted is a reason to suppose NO growth of the launch operations team â€“ which menas groth of the manufacturing team or perhaps one of the other two teams. So what about growth of the R&Dteam? They mainly will be developping engines and it will be one engine after the other â€“ not all at once. When the first Merlin 1B is ready for a first launch they will work on clustering/bundling them for the Falcon 9. And after that they will work on using Falcon 9first stages as boosters of the Falcon 9 Heavy. This doesnâ€™t sound as if any growth is to be expected. And the Administration Team? Paperwork, phoning, hiring, ordering repairservices and the like, selling launches â€“ I donâ€™t think that that team will growth because of the rockets â€“ they will grow when the business grows. There is one thing that has not been taken into account regarding the growth of teams â€“ the Dragon, The Dragon might cause growth of the R&D Team and the Manufacturing Team â€“ but first of all no numbers about the Dragon are available that could be applied to handle this properly. And next SpaceX is developing the Dragon with partners who are doing R&D and manufacturing also. Last but not least it can be assumed here that the majority of employees to be hired for the Dragon will be hired after 2008 So I consider the manufactureringteam to be the only one growing here. Like I already said earlier I have in mind to apply alternative numbers/values also to check what changes then and by how much it does change. This means that the structure of the salaries is changing by the years â€“ the share of the three notgrowing teams is dimishing: Code: team 2006 2007 2008 Launch Operations Team 25. 25 25 R&D 51 51 51 Administration 22 22 22 nongrowing 98 98 98 Manufacturing 157 243 335 Then the shares are Code: team 2006 2007 2008 nongrowing 0 384313725 0,287390029 0.243792325 Manufacturing 0.615686275 0.712609971 0.756207675 These numbers include one correction and several roundings. These shares now have to be multiplied by the factors and added on then â€“ the shares of the nongrowing teams by 0.333... because of three rockets and equal distribution of the salaries, the shares of the manufacturing team by the other factor because of inequal distirbution. Because of the application of g,h,i and j to salaries of different years I now prefer to leave away the labour costs share and auxiliary equations: Falcon 9: 10 * X + f * 1/n9 * g * L2008 + pr9 + npr9 + p9 = F9 â€“ (a + b) Falcon 9 Heavy: 28 * X + f * 1/n9h * h * L 2008 + pr9h + npr9h + p9h = F9H â€“ (3 * a + b) Falcon 1: 1 * Z + 1 * Y + f * 1/n1 * i * L2006 + pr1 + npr1 + p1 = F1 â€“ (e + f) Falcon 5: 6 * X + f * 1/n5 * j * L2007 + pr5 + npr5 + p5 = F5  (c + d) Similarity: Z = X Cash Flow: n9 * pr9 + n9 * npr9 + n9h * pr9h + n9h * npr9h + n1 * pr1 + n1 * npr1 + n5 * pr5 + n5 * npr5  r * I  np < n9 * F9 + n9h * F9H + n1 * F1 + n5 * F5 â€“ L Investment: I = 1 * Z + 1 * Y + i1 * L2006 + j1 * L2006 + R Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
The shares and factors result in the following values:
g = 0.333 * 0.243792325 + 0.667 * 0.756207675 = 0.58540255833333333333333333333333 rounded to 0.59 h = 0.333 * 0.243792325 + 0.333 * 0.756207675 = 0.333â€¦ Since I already said a few posts earlier that I would apply the exact numbers of employees of that quarter of the year the first launch of a rocket is done in letâ€™s think about it. What Iâ€™ve said has to do with the circumstance that the number of employees is growing month y month and thus quarter by quarter. The number by which it grows is between 8 and 9 per month and thus 24 to 27 â€“ 27 merely â€“ per quarter. This means that for the first quarter of a year the exact number is below the quarter of the average number of employees of that year while it is above it in the third and the last quarter of that year. In the second quarter it is equal to the average. To do this properly the average per quarter must be calculated. In the equation system L2006, L2007 and L2008 have to be replaced by L2006Q1 and so on in the four equations of the rockets an in the investment equation. The effect of doing so would be increased values of X, Y and Z (at least) â€“ which would mean safety margins included into the investment into each rocket. On the other hand doing NOT so would include safety margins into the variable costs â€“ and thus the lower boundary of the launch and flight costs. Because I delayed the calculations very much in between I prefer to apply both alternatives and start with keeping L2006 to L2008. So letâ€™s insert all known numbers now: Falcon 9: 10 * X + 0.25 * 1/1 * 0.59 * 40889610.24 + 169130 + npr9 + p9 = 35 mio â€“ (20958.4082353887 + 23151.7300274643) Falcon 9 Heavy: 28 * X + 0.25 * 1/1 * 0.33 * 40889610.24 + 46553 + npr9h + p9h = 78 mio â€“ (3 * 20958.4082353887 + 23151.7300274643) Falcon 1: 1 * Z + 1 * Y + 0.25 * 1/2 * 0.29 * 24080486.40 + 16402,1 + npr1 + p1 = 6.7 mio â€“ (5754,08494834638 + 306,884530578474) Falcon 5: 6 * X + 0.25 * 1/1 * 0.71 * 32201748.48 + 91780 + npr5 + p5 = 18 mio  (26807.2663 + 11372.7797) Similarity: Z = X Cash Flow: 0 * pr9 + 0 * npr9 + 0 * pr9h + 0 * npr9h + n1 * pr1 + n1 * npr1 + 0 * pr5 + 0 * npr5  r * I  np < 0 * 35 mio + 0 * 78 mio + 1 * 6.7 mio + 0 * 18 mio â€“ 24080486.40 Investment: I = 1 * Z + 1 * Y + 0.1 * 24080486.40 + 0.52 * 24080486.40 + R I didnâ€™t insert numbers for n1 into the Cash Flowequation because the three versions of the launch manifest list at least two different numbers of launches. It also is looking as if the equations are adjusted to the seond version of the launch manifest at present because of applying L2008 for the Falcon 9 â€“ I have to check that. The Falcon 9 Heavy includes a share of the labour costs below the share included into the Falcon 9 â€“ a bit more than half that share. This can be considered to be justified by the circumstance that two additional first stages are applied only while the second stage is left unchanged but newly constructed for the Falcon 9. So after getting results from this L2008 has to be replaced by L2007 in the Falcon 9equation(s) and two alternative results have to be calculated per case â€“ four results to be expected if I havenâ€™t forgotten something. Next additional four results might be got by replacing the L2006 etc. by L2006Q1 etc. Dipl.Volkswirt (bdvb) Augustin (Political Economist. 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
I forgot to insert the value for pr1 and for I into the Investmentequation into the Cash Flowequation which I have done in this post now.
Since all numbers are inserted now the equations can be modified. This is done in the appendix. The first three modifications result in the following version of the equation system: Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * Z + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Similarity: Z â€“ X = 0 Cash Flow: n1 * 16402.1 + n1 * npr1  r * I  np < 1 * 6.7 mio â€“ 24080486.40 Investment: 1 * Z + 1 * Y + R = 100 mio  0.62 * 24080486.40 The unknowns here are
npr9 p9 npr9h p9h Z Y npr1 p1 npr5 p5 r np R n1 simply isnâ€™t inserted yet. So there are 14 unknowns at present and 7 equations. This is the consequence of the nprs. If they are combined with the profits p into one variable the number of unknowns is reduced to 10. I is NOT set here but is known â€“ this is handled in the next modifications. r and np will be set and then a function is got. But letâ€™s do more modifications first. The next version of the equation system to be looked at is Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1  r * (1 * X + 1 * Y + R + 0.62 * 24080486.40)  np < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 There is a known value on the left side of the Cash Flowequation now because the rate of depreciation hasnâ€™t been set yet. This has to be thought about in the next post as well as about np. Now 13 unknowns now and 6 equations are left. Iâ€™ll go on later. Dipl.Volkswirt (bdvb) Augustin (Political Economist) Appendix First 3 Modifications 1. Modification: Shift of knowns to the right sides and unknowns to the left sides Falcon 9: 10 * X + npr9 + p9 = 35 mio â€“ (20958.4082353887 + 23151.7300274643) â€“ (0.25 * 1/1 * 0.59 * 40889610.24 + 169130) Falcon 9 Heavy: 28 * X + npr9h + p9h = 78 mio â€“ (3 * 20958.4082353887 + 23151.7300274643) â€“ (0.25 * 1/1 * 0.33 * 40889610.24 + 46553) Falcon 1: 1 * Z + 1 * Y + npr1 + p1 = 6.7 mio â€“ (5754.08494834638 + 306.884530578474) â€“ (0.25 * 1/2 * 0.29 * 24080486.40 + 16402.1) Falcon 5: 6 * X + npr5 + p5 = 18 mio  (26807.2663 + 11372.7797) â€“ (0.25 * 1/1 * 0.71 * 32201748.48 + 91780) Similarity: Z â€“ X = 0 Cash Flow: 0 * pr9 + 0 * npr9 + 0 * pr9h + 0 * npr9h + n1 * pr1 + n1 * npr1 + 0 * pr5 + 0 * npr5  r * I  np < 0 * 35 mio + 0 * 78 mio + 6.7 mio + 0 * 18 mio â€“ 24080486.40 Investment: 1 * Z + 1 * Y + R = 100 mio â€“ (0.1 * 24080486.40 + 0.52 * 24080486.40) 2. Modification: Calculation of all terms completely consisting of knowns Falcon 9: 10 * X + npr9 + p9 = 35 mio â€“ 44110.138262853 â€“ (0.1475 * 40889610.24 + 169130) = 35 mio â€“ 44110.138262853 â€“ 0.1475 * 40889610.24  169130 = 35 mio â€“ 213240.138262853 â€“ 0.1475 * 40889610.24 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 78 mio â€“ (62875.2247061661 + 23151.7300274643) â€“ (0.04125 * 40889610.24 + 46553) = 78 mio â€“ 86026,9547336304 â€“ (0.04125 * 40889610.24 + 46553) = 78 mio â€“ 86026.9547336304 â€“ 0.04125 * 40889610.24  46553 = 78 mio â€“ 132579.9547336304 â€“ 0.04125 * 40889610.24 = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * Z + 1 * Y + npr1 + p1 = 6.7 mio â€“ 6060.969478924854 â€“ (0.03625 * 24080486.40 + 16402.1) = 6.7 mio â€“ 6060.969478924854 â€“ 0.03625 * 24080486.40 â€“ 16402.1 = 6.7 mio â€“ 22463,069478924854 â€“ 0,03625 * 24080486.40 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 18 mio â€“ 38180.046 â€“ (0.1775 * 32201748.48 + 91780) = 18 mio â€“ 38180.046 â€“ 0.1775 * 32201748.48  91780 = 18 mio â€“ 129960.046 â€“ 0.1775 * 32201748.48 = 17870039.954 â€“ 0.1775 * 32201748.48 Similarity: Z â€“ X = 0 Cash Flow: 0 * pr9 + 0 * npr9 + 0 * pr9h + 0 * npr9h + n1 * 16402.1 + n1 * npr1 + 0 * pr5 + 0 * npr5  r * I  np < 0 * 35 mio + 0 * 78 mio + 6.7 mio + 0 * 18 mio â€“ 24080486.40 Investment: I â€“ (1 * Z + 1 * Y + R) = 0.62 * 24080486.40 Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * Z + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Similarity: Z â€“ X = 0 Cash Flow: 0 * pr9 + 0 * npr9 + 0 * pr9h + 0 * npr9h + n1 * 16402.1 + n1 * npr1 + 0 * pr5 + 0 * npr5  r * I  np < 0 * 35 mio + 0 * 78 mio + 6.7 mio + 0 * 18 mio â€“ 24080486.40 Investment: 1 * Z + 1 * Y + R = 100 mio  0.62 * 24080486.40 The labour costterm is NOT calculated to keep it easier to replace the value labour cost. 3. Modification: Elimination of multiplications by 0 Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * Z + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Similarity: Z â€“ X = 0 Cash Flow: n1 * 16402.1 + n1 * npr1  r * I  np < 6.7 mio â€“ 24080486.40 Investment: 1 * Z + 1 * Y + R = 100 mio  0.62 * 24080486.40 Modifications 4 and 5 4. Modification: Application of the Similarityequation by insertion X for Z Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1  r * I  np < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 5. Modification: Insertion of I = 1 * X + 1 * Y + R + 0.62 * 24080486.40 = 100 mio Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1  r * (1 * X + 1 * Y + R + 0.62 * 24080486.40)  np < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Regarding the new provisions np and the rate of depreciation r the launch manifests are of help â€“ in particular for the new provisions they are the only data source.
But regarding the rate of depreciation there are more approaches:
2. loss of two Falcon 1s 3. average including one of the other alternatives and the nonrocketinvestments (buildings 30 years, machines 10 years) 4. maximum number of launches of a rocket 5. maximum number of launches over all rockets â€¦ The alternative values of np are $ 13.4 mio in version1 and $ 20.1 mio in version 2 and 3. The alternative values of r are Code: version 1 of launch manifest 33.333â€¦% by three Falcon 1launches version 2 of launch manifest 14.2857â€¦% by six Falcon 1launches version 2 of launch manifest 4.56% by six Falcon 1launches plus the Air Forcecontract version 3 of launch manifest 16.666â€¦% by six Falcon 1launches version 3 of launch manifest 4.75% to 5% by six Falcon 1launches plus the Air Forcecontract loss of first Falcon 1 5% and more loss of two Falcon 1s 10% and more average 5.75% to 6% 15 years in average for buildings and machines maximum number of launches 14.2857â€¦% maximum over all rockets 10% maximum over all rockets 4% plus the Air Forcecontract If the price of one Falcon 1launch not accounting for reusability would be taken as depreciation then this would be a rate of depreciation of 6.7%. The average listed is 5.75% to 6%  which is less but close to it. The least rate is 4% and is based on rockets requiring an additional investment of $ 100 mio according to Elon Musk â€“ so I donâ€™t want to apply the 4%. Because of all this I am going to apply 5% here. Inserting the smaller np and the rate of depreciation chosen the equation system is Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * (1 * X + 1 * Y + R + 0.62 * 24080486.40) â€“ 13.4 mio < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 6. Modification: Calculation of all terms completely consisting of knowns Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * 1 * X + 0.05 * 1 * Y + 0.05 * R + 0.05 * 0.62 * 24080486.40 â€“ 13.4 mio < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * X + 0.05 * Y + 0.05 * R + 0.031 * 24080486.40 â€“ 13.4 mio < 6.7 mio â€“ 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 7.Modification: Shift of knowns to the right sides and unknowns to the left sides Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * X + 0.05 * Y + 0.05 * R < 6.7 mio â€“ 24080486.40 â€“ (0.031 * 24080486.40 â€“ 13.4 mio) Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 6. Modification: Calculation of all terms completely consisting of knowns Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * X + 0.05 * Y + 0.05 * R < 6.7 mio â€“ 24080486.40 â€“ 0.031 * 24080486.40 + 13.4 mio Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 Falcon 9: 10 * X + npr9 + p9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + npr9h + p9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: 1 * X + 1 * Y + npr1 + p1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + npr5 + p5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1 â€“ 0.05 * X + 0.05 * Y + 0.05 * R < 20.1 mio â€“ 1.031 * 24080486.40 Investment: 1 * X + 1 * Y + R = 100 mio  0.62 * 24080486.40 N1 isnâ€™t inserted yet although the versions of the launch manifest are applied â€“ the reason is that the number of possible launches is used while n1 is the actual number of launches. The unknowns left now are
npr9 p9 npr9h p9h Y npr1 p1 npr5 p5 R Which are 11 unknowns at 6 equations. 4 unknowns can be combined with 4 other unknowns â€“ resulting in 7 unknowns at 6 equations which means a function. The unknowns to be combined will be looked at in the next post. Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
The unknowns to be combined are
npr9h with p9h npr1 with p1 npr5 with p5 The problem behind it is the question how the values of four of them could be got. The nprs are variable nonpropellant costs per launch/flight similar to or like the propellant costs. There are no equations they could be calculated by â€“ it would be unusual if such equations would exist. The ps are the profits per launch/flight and usually result from equations. In so far both the nonpropellant costs and the profits are very similar to each other â€“ and the situation once more shows that the present approach is economically impossible and against the nature of the eight unknowns. It seems that only values for combinations of each npr with the according p can be got. Then it could be thought or pondered about the distribution of the values over the two combined unknowns. The nprs may include refurbishments. It is NOT clear however if they include labour costs of the refurbishments. Neither SpaceX nor Elon Musk have talked about refurbishments (not in any detail at least). At present I could imagine that the launch operation team also does the refurbishments and the rocket equations mean that the refurbishments are included into the prices â€“ which is required to be able to cover those costs and to get into the profit zone one day. So letâ€™s add on the nprs and the ps to margins ms: npr9 + p9 = m9 npr9h + p9h = m9h npr1 + p1 = m1 npr5 + p5 = m5 There is one possible access to the value of a npr â€“ npr1 is explicitly a part of the Cash Flowequation. Perhaps it can be calculated directly. The other nprs may be got by assuming the ps to be zero. Before going on it is required to recognize that there are errors in the mathematical operations in the previous post at modifications of the Cash Flowequation â€“ beginning at the 6. modification. I also detected that it would be more proper to NOT insert the Investmentequation into the Cash Flowequation as 5. modification. Also the value for np must be removed again because it is linked to n1 directly. So I start again at the 5. modification: 5. Modification: Multiplying away factor = 1 in two equations Falcon 9: 10 * X + m9 = 34786759.861737147 â€“ 0.1475 * 40889610.24 Falcon 9 Heavy: 28 * X + m9h = 77867420.0452663696 â€“ 0.04125 * 40889610.24 Falcon 1: X + Y + m1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Falcon 5: 6 * X + m5 = 17870039.954 â€“ 0.1775 * 32201748.48 Cash Flow: n1 * 16402.1 + n1 * npr1  r * I  np < 6.7 mio â€“ 24080486.40 Investment: X + Y + R = 100 mio  0.62 * 24080486.40 6. Modification: Solution for X from Falcon 9equation â€“ subtraction of m9 Falcon 9: 10 * X = 34786759.861737147 â€“ 0.1475 * 40889610.24 â€“ m9 7. Modification: Solution for X from Falcon 9equation â€“ division by 10 Falcon 9: X = 3478675.9861737147 â€“ 0.01475 * 40889610.24 â€“ 0.1 * m9 = 2875554.2351337147 â€“ 0.1 * m9 At this point economical thoughts about the result should be done. m9 consists of costs and a profit. So can m9 be negative? A profit can be negative and thus be a loss â€“ but can a launch price include a loss? This might be the case if launches of that rocket are driving the business of launching other rockets. If launches of the rocket the launch price of includes a loss is NOT offered the entrepreneur wouldnâ€™t get customers for the other rockets. In THAT case a price might include a loss. Negative costs would be revenues â€“ and revenues are got via the price. So the costs included into m9 canâ€™t be negative no way. So itâ€™s possible that m9 is negative because of business and then other rockets would crossfinance the loss. The method applied at present doesnâ€™t account for that. What are the boundaries of m9? The investment into the Merlin 1B (X) canâ€™t be negative â€“ meaning that m9 canâ€™t be higher than $ 28,755,542.351337147. Then X would be zero. How reasonable is the maximum value of m9? Assumed it is entirely npr9 then such a value is economically nonsense. The nonpropellant costs not only would be a multiple of the propellant costs â€“ they would be astronomical in comparison to the investment of 0. Assumed furthermore the nonpropellant costs are refurbishment costs then the refurbishment would be astronomical in comparison to the investment itself which is 0. Since the investment itself is higher than 0 that high refurbishment costs are unlikely. This also means that m9 canâ€™t be entirely profit no way. So m9 will be no higher than the half of the maximum listed above. Next a negative m9 is limited by the circumstance that the resulting investment into the Merlin (=X) effects the investment into and the profits of the other rockets. At least one of them will be intended to yield profits. The more negative m9 is the more crossfinancing will be required and the higher the result of the equation got by the 7. modification. At present the ONLY rocket available using a Merlin (=X) is the Falcon 1 â€“ because of this I am doubting if the launch price of the Falcon 1 inlcudes a loss. Of course this doesnâ€™t mean yet that m9 is not negative since it is not the margin of the price for a Falcon 1launch. Can a loss included into the launch price be as high as the investment into the rocket? I am doubting that very much â€“ it would mean the loss of the complete investment into that rocket. The rocket would still be there because it is reusable but each launch of the rocket would reduce the capital left by a significant amount. Of course it canâ€™t be said for sure what portion of the investment the included loss might be but the upper boundary seems to be known now. So m9 will be between $ â€“ 28,755,542.351337147 and $ + 14,377,771.1756685735 â€“ meaning that X will be between $ + 1,437,777.11756685735 and $ + 5,751,108.4702674294. But it is possible to find it out in detail. Letâ€™s have a look to the results of the 7. Modification for the Falcon 9 Heavy and the Falcon 5: Falcon 9 Heavy: 2,720,740.129388084 â€“ 0.03571428â€¦ * m9h Falcon 5: 2,025,704.9331333â€¦  0.1666â€¦ * m5 The earlier contradictional results show up again but completed by a term the value of isnâ€™t known at present. This is what the equation system and the margins and their components are providing and what their purpose is (although it needs to be modified later because of economical impossibilities). The Falcon 9 Heavy seems to allow for a larger range of values of m9h than is allowed for m9 while the Falcon 5 seems to allow for a smaller range of m5 than for m9. This I recognize by a look on the factors. But all the ranges are intercepting each other or they may form a hierarchy â€“ this enables for approximations if required or wanted. What about the Falcon 1? This rocket is the only one in the list where the two stages have different engines. So at this point the equation allows for a joint result only: 5,804,619.298521075 â€“ m1. The range in this case is much more smaller than those for the other rockets. m1 canâ€™t be larger than $ 2,902,309.649260537 and not smaller than $  6.7 mio. Then the both engines together require an investment of $ 2,902,309.649260537 minimum and 9,602,309.649260537 maximum. But it can be found out more precisely and in more detail. Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Like already mentioned the margins arenâ€™t adjusted to each other up to now. But this can be handled now. The three alternative equations for X MUST have the same results since each Merlin of several instances of the same version have to have the same costs and price. This establishes functions by which m9h and m5 can be calculated from m9 â€“ which I chose here because the Falcon 9 is the first of those three that will be launched.
8. Modification: Equalizing solutions for X Falcon 9 and Falcon 9 Heavy: X = 2875554.2351337147 â€“ 0.1 * m9 = 2720740.129388084 â€“ 0.03571428â€¦ * m9h Falcon 9 and Falcon 5: X = 2875554.2351337147 â€“ 0.1 * m9 = 2025704.9331333â€¦  0.1666â€¦ * m5 9. Modification: Subtraction of the constant of the Falcon 9 Heavyequation Falcon 9 and Falcon 9 Heavy: 154814.1057456307 â€“ 0.1 * m9 = 0.03571428â€¦ * m9h Falcon 9 and Falcon 5: 849849.3020003814 â€“ 0.1 * m9 = 2025704.9331333â€¦  0.1666â€¦ * m5 10. Modification: Division by the factors of m9h or m5 Falcon 9 and Falcon 9 Heavy: 4334795.6544449643 â€“ 2.8000004480 * m9 = m9h Falcon 9 and Falcon 5: 5099095.8120022882 â€“ 0.6 * m9 = m5 At this point a better look at the boundaries already mentioned is possible since the values of the boundaries can be inserted to get real sets of values linked to each other. It also is possible to find additional extreme values where at least one of the margins is zero. This way it can be seen how the margins behave in concert â€“ including the margins to be got for m9h and m5: Code: m9 kind m9h m5 ruled out by  invalid  28755542.3513378831 m9h=mn  76180735.8117840819  12154229.5988004417 m9 28755542.3513368137 m5=min  76180735.8117810875  12154229.5987998 m9  valid  14377771.1756685735 m9=max  35922970.0786685282  3527566.8933988559 8498493.0200038136 m5 =0  19460988.6088905869 0 1548141.0574563466 m9h=0 0 4170211.1775284802 0 m9 =0 4334795.6544449643 5099095.8120022882  1630031.6456626863 m5=max 8898884.9925546633 6077114.7993999  invalid   12055559.5894844216 m9h=mx 38090367.905892041 12332430.9656929412 m5 â€“ 28755542.351337147 m9=min 84850327.1206719492 22352421.2228045764 m9h As can be seen in the table above the minimum values of m9h and m5 are invalid because the value of m9 would be far above the maximum valid value of m9 then. The minimum value of m9 is invalid also because m9 and m5 are above their maxima then. And the maximum value of m9h is invalid also because m5 is still above its maximum value then. The valid values consist of three different groups â€“ one where m9 is positive and at least m9h is negative, a second where none of the three is negative and a third where m9 is negative while both of the others are positive. If you prefer to assume that all the margins are positive and none is negative then m9 is somewhere between $ 1,548,141 and $ 0 with m9h being between $ 0 and $ 4,334,795 and m5 between $ 4,170,211 and $ 5,099,095. So letâ€™s have a look at the values of X resulting now â€“ by applying the equation Falcon 9: X = 2875554.2351337147 â€“ 0.1 * m9: Code: m9 kind X ruled out by  invalid  28755542.3513378831 m9h=mn  0.0000000736 m9 28755542.3513368137 m5=min 0.0000000333 m9  valid  14377771.1756685735 m9=max 1437777.1175668574 8498493.0200038136 m5 =0 2025704.9331333333 1548141.0574563466 m9h=0 2720740.1293880800 0 m9 =0 2875554.2351337147  1630031.6456626863 m5=max 3038557.3996999833  invalid   12055559.5894844216 m9h=mx 4081110.19408215686 m5 â€“ 28755542.351337147 m9=min 5751108.4702674294 m9h Accoding to this table the investment into the Merlin (X) is between $ 1.434 mio and $ 3.038 mio at valid values for all three margins and between $ 2.721 mio and $ 2.875 mio if it is preferred to assume positive values for all three margins. In so far reasonable and workable approximations are possible already and even values for the actual launch prices can be calculated. In particular it seems to be possible to get values for X even if Z =X is invalid. But letâ€™s go on here. m1 and Y havenâ€™t been considered again yet. In the previous post a joint result for X and Y was possible only: X + Y = 5804619.298521075 â€“ m1 with 2902309.649260537 >= m1 >=  6.7 mio. Applying the valid values of X this equation is turned into the following versions:
2025704.9331333333 + Y = 5804619.298521075 â€“ m1 2720740.1293880800 + Y = 5804619.298521075 â€“ m1 2875554.2351337147 + Y = 5804619.298521075 â€“ m1 3038557.3996999833 + Y = 5804619.298521075 â€“ m1 The way to equations for Y is: step 1
Y = 5804619.298521075  2025704.9331333333 â€“ m1 Y = 5804619.298521075  2720740.1293880800 â€“ m1 Y = 5804619.298521075  2875554.2351337147 â€“ m1 Y = 5804619.298521075  3038557.3996999833 â€“ m1 step 2
Y = 3778914.3653877417 â€“ m1 Y = 3083879.169132995 â€“ m1 Y = 2929065.0633873603 â€“ m1 Y = 2766061.8988210917 â€“ m1 The upper boundary and the lower boundary of m1 could be inserted to get alternative values of Y but it is not clear yet what the proper value or the proper range of values inside the range already list might be. Itâ€™s a temptation to look at the boundaries of m1 by the second list â€“ but that would be misleading because of the circumstance that there are several alternative equations. So the unknowns not looked at yet â€“ m1, Y, R â€“ need to be found out by additional modifications to be done later. Up to this point it is still looking as if simply a value has been found Andy Hill was assuming a longer time ago already. But the intention here is to look far beyond that value â€“ to profits, refurbishments, also to the links between the margins etc. of the particular rockets and much more. Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Before looking into the remaining unknowns systematically and in detail letâ€™s think about m1 a bit. If all three other margins are supposed to be positive then it would be consequent to consider m1 to be also positive. But there is another essential aspect too â€“ is it reasonable to include a loss into the launch price of the only reusable rocket SpaceX have at present? If so then it should be a marginal loss only because the whole initial investment of $ 100 mio would be lost relatively quickly. And this thought also holds if the one of or all other margins were supposed to be negative.
Another question again is if the Kestrel (Y) is cheaper or more expensive than the Merlin. Then from the previous post the following must be concluded: If the Kestrel is supposed to be cheaper and m9, m9h and m5 are considered to be positive then m1 logically must be positive â€“ and it must be the more positive the lower the investment into the Merlin (X) is assumed to be. One argument seems to be speaking for the Kestrel to be cheaper â€“ it is expendable and thus should be kept cheap the more. To apply the equation system for getting systematical insights letâ€™s consider Y and the three equations not applied yet now. First of all there is the Investmentequation Investment: X + Y + R = 100 mio  0.62 * 24080486.40 The equation includes the Kestrel (Y). This seems â€“ and really IS â€“ an error I kept until now consciously. It really is an error because the Kestrel is part of the expendable second stage of the Falcon 1 and thus is part of the variable costs â€“ but it is not included into the variable nonpropellantcosts. The reason causing the error was â€“ among others â€“ that development costs are investments of particular kind and that a portion of the investment of $ 100 mio must be considered to have gone into the development. Another reason or merely cause was that the second stage of the other three rockets explicitly will be reusable and NOT expended. To keep the error enables to illustrate the economical effect of reusability. So first here the two alternative versions â€“ correct with Kestrel and second stage expendable and wrong with Kestrel and second stage reusable:
Falcon 1: X + Y + m1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Cash Flow: n1 * 16402.1 + n1 * npr1 + n1 * Y  r * I  np < 6.7 mio â€“ 24080486.40 Investment: X + R = 100 mio  0.62 * 24080486.40 b) reusable Y â€“ wrong original version Falcon 1: X + Y + m1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Cash Flow: n1 * 16402.1 + n1 * npr1  r * I  np < 6.7 mio â€“ 24080486.40 Investment: X + Y + R = 100 mio  0.62 * 24080486.40 There are two alternative ways now â€“ to insert $ 100 mio for I or to insert the Investmentequation for I. I insert $ 100 mio now â€“ I keep the knowns uninserted but handle them as inserted: 6. modification
Falcon 1: X + Y + m1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Cash Flow: n1 * 16402.1 + n1 * npr1 + n1 * Y  r * 100 mio  np < 6.7 mio â€“ 24080486.40 Investment: X + R = 100 mio  0.62 * 24080486.40 b) reusable Y â€“ wrong original version Falcon 1: X + Y + m1 = 6677536.930521075146 â€“ 0.03625 * 24080486.40 Cash Flow: n1 * 16402.1 + n1 * npr1  r * 100 mio  np < 6.7 mio â€“ 24080486.40 Investment: X + Y + R = 100 mio  0.62 * 24080486.40 7. modification
Falcon 1: X = 6677536.930521075146 â€“ 0.03625 * 24080486.40  Y + m1 Cash Flow: n1 * Y < 6.7 mio â€“ 24080486.40  n1 * 16402.1  n1 * npr1 + r * 100 mio + np Investment: X = 100 mio  0.62 * 24080486.40  R b) reusable Y â€“ wrong original version Falcon 1: X = 6677536.930521075146 â€“ 0.03625 * 24080486.40  Y  m1 Cash Flow: n1 * npr1 < 6.7 mio â€“ 24080486.40  n1 * 16402.1 + r * 100 mio + np Investment: X = 100 mio  0.62 * 24080486.40  Y  R 8. modification
Falcon 1: X = 6677536.930521075146 â€“ 0.03625 * 24080486.40  Y + m1 Cash Flow: Y < 6.7 mio/n1 â€“ 24080486.40/n1  16402.1  npr1 + r * 100 mio/n1 + np/n1 Investment: X = 100 mio  0.62 * 24080486.40  R b) reusable Y â€“ wrong original version Falcon 1: X = 6677536.930521075146 â€“ 0.03625 * 24080486.40  Y  m1 Cash Flow: npr1 < 6.7 mio/n1 â€“ 24080486.40/n1  16402.1 + r * 100 mio/n1 + np/n1 Investment: X = 100 mio  0.62 * 24080486.40  Y  R As can be seen in the 8. modification of the e quations not solved yet the two version prefer different results of the Cash Flowequation â€“ while the wrong version results in the value of npr1 the correct version seems to result in a value of the investment into a Kestrel (Y) while the npr1 is treated as if it is known. To do like in the correct version is suggested by the circumstance that npr1 is part of m1 because of m1 = npr1 + p1. The wrong version on the other hand delivers a value for npr1 which seems to be of nearly no use but might be a hint to the value of npr1 in the correct version. The other equations of the wrong version seem to be of no use regarding the Kestrel. So letâ€™s concentrate on the Cash Flowequation now â€“ using r = 0.05 but alternatively 2 and 3 for n1 and alternatively 13.4 mio and 20.1 mio for np: 9. modification
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 6.7 mio/2 â€“ 24080486.40/2  16402.1  npr1 + 0.05 * 100 mio/2 + 13.4 mio/2 ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 6.7 mio/3 â€“ 24080486.40/3  16402.1  npr1 + 0.05 * 100 mio/3 + 20.1 mio/3 b) reusable Y â€“ wrong original version ba) n1 = 2 np = 13.4 mio Cash Flow: npr1 < 6.7 mio/2 â€“ 24080486.40/2  16402.1 + 0.05 * 100 mio/2 + 13.4 mio/2 bb) n1 = 3 np = 20.1 mio Cash Flow: npr1 < 6.7 mio/3 â€“ 24080486.40/3  16402.1 + 0.05 * 100 mio/3 + 20.1 mio/3 10. modification
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 3.35 mio â€“ 12040243.20  16402.1  npr1 + 2.5 mio + 6.7 mio ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 2.2333â€¦ mio â€“ 8026828.80  16402.1  npr1 + 1.666â€¦ mio + 6.7 mio b) reusable Y â€“ wrong original version ba) n1 = 2 np = 13.4 mio Cash Flow: npr1 < 3.35 mio â€“ 12040243.20  16402.1 + 2.5 mio + 6.7 mio bb) n1 = 3 np = 20.1 mio Cash Flow: npr1 < 2.2333â€¦ mio â€“ 8026828.80  16402.1 + 1.666â€¦ mio + 6.7 mio 11. modification
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 5.85 mio â€“ 12040243.20  16402.1  npr1 + 6.7 mio ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 3.9 mio â€“ 8026828.80  16402.1  npr1 + 6.7 mio b) reusable Y â€“ wrong original version ba) n1 = 2 np = 13.4 mio Cash Flow: npr1 < 5.85 mio â€“ 12040243.20  16402.1 + 6.7 mio bb) n1 = 3 np = 20.1 mio Cash Flow: npr1 < 3.9 mio â€“ 8026828.80  16402.1 + 6.7 mio 11. modification
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 12.55 mio â€“ 12056645.30  npr1 ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 10.6 mio â€“ 8043230.90  npr1 b) reusable Y â€“ wrong original version ba) n1 = 2 np = 13.4 mio Cash Flow: npr1 < 12.55 mio â€“ 12056645.30 bb) n1 = 3 np = 20.1 mio Cash Flow: npr1 < 10.6 mio â€“ 8043230.90 12. modification  results
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 493354.7  npr1 ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 2556769.1  npr1 b) reusable Y â€“ wrong original version ba) n1 = 2 np = 13.4 mio Cash Flow: npr1 < 493354.7 bb) n1 = 3 np = 20.1 mio Cash Flow: npr1 < 2556769.1 It seems that the wrong version tells what must be concluded economically from the fact that Y canâ€™t be negative because of being an investment or something having a price or at least production costs. If n1 = 2 is applied then the Kestrel (Y) would cost less than $ 493,354.7 which is sounding very low in comparison to the Merlin (X) but might be possible under the aspect that the Kestrel is expendable. If on the other hand n1 = 3 is applied the Kestrel (Y) would cost less than $ 2,556,769.1 which sounds reasonable â€“ even in comparison to the Merlin(X). Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Next the Falcon 1equation can be solved. The wrong version of the CashFlowequation and the Investmentequation wouldnâ€™t result in something usefull but in an equation leading to functions where there are two independent variables instead of only one.
So I apply the correct version only from now on. Y can be inserted into the Falcon 1equation now. Since the Cash Flowequation is kept an inequation up to now the Falcon 1equation is turned into an inequation also now. Since Y has a negative sign there the inequationsign is reversed: 9. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: X > 6677536.930521075146 â€“ 0.03625 * 24080486.40 â€“ (493354.7  npr1) + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: X > 6677536.930521075146 â€“ 0.03625 * 24080486.40 â€“ (2556769.1  npr1) + m1 10. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: X > 6677536.930521075146 â€“ 0.03625 * 24080486.40 â€“ 493354.7 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: X > 6677536.930521075146 â€“ 0.03625 * 24080486.40 â€“ 2556769.1 + npr1 + m1 11. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: X > 6184182.230521075146 â€“ 0.03625 * 24080486.40 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: X > 4120767.830521075146 â€“ 0.03625 * 24080486.40 + npr1 + m1 12. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: X > 6184182.230521075146 â€“ 872917.632 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: X > 4120767.830521075146 â€“ 872917,632 + npr1 + m1 12. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: X > 5311264.598521075146 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: X > 3247850.198521075146 + npr1 + m1 Because of the preliminary results for X got earlier npr1 + m1 has to be negative it seems â€“ and since npr1 as nonpropellant variable costs including possible refurbishments canâ€™t be negative it seems to mean that the profit p1 (from m1 = npr1 + p1) is negative. But simply letâ€™s insert the equation which calculates X from m9: 13. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: 2875554.2351337147 â€“ 0.1 * m9 > 5311264.598521075146 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: 2875554.2351337147 â€“ 0.1 * m9 > 3247850.198521075146 + npr1 + m1 14. modification a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: â€“ 0.1 * m9 > 2435710.363387360446 + npr1 + m1 ab) n1 = 3 np = 20.1 mio Falcon 1: â€“ 0.1 * m9 > 372295.963387360446 + npr1 + m1 15. modification â€“ multiplication by 10 reverses the inequationsign a) expendable Y â€“ corrected new version aa) n1 = 2 np = 13.4 mio Falcon 1: m9 <  24357103.63387360446  10 * npr1 â€“ 10 * m1 ab) n1 = 3 np = 20.1 mio Falcon 1: m9 <  3722959.63387360446 â€“ 10 * npr1 â€“ 10 * m1 As inequations these are telling anything only if assumptions about npr1 and m1 are applied. And since npr1 allways is positive it allows for a positive m9 only if m1 is negative which means that it includes a loss. Because of this the Cash Flowequation as well as the resulting equations above now must be turned into real equations very cautiously. The CashFlowINequation applied is
aa) n1 = 2 np = 13.4 mio Cash Flow: Y < 493354.7  npr1 ab) n1 = 3 np = 20.1 mio Cash Flow: Y < 2556769.1  npr1 The Falcon 1equation got is
aa) n1 = 2 np = 13.4 mio Falcon 1: m9 <  24357103.63387360446  10 * npr1 â€“ 10 * m1 ab) n1 = 3 np = 20.1 mio Falcon 1: m9 <  3722959.63387360446 â€“ 10 * npr1 â€“ 10 * m1 Y canâ€™t be negative: aa) 0 < Y < 493354.7  npr1 ab) 0 < Y < 2556769.1  npr1 So aa) 0 < npr1 < 493354.7 ab) 0 < npr1 < 2556769.1 is valid. Because of m1 = npr1 + p1 the Falcon 1equation can be written as
aa) n1 = 2 np = 13.4 mio Falcon 1: m9 <  24357103.63387360446  10 * npr1 â€“ 10 * (npr1 + p1) ab) n1 = 3 np = 20.1 mio Falcon 1: m9 <  3722959.63387360446 â€“ 10 * npr1 â€“ 10 * (npr1 + p1)
aa) n1 = 2 np = 13.4 mio Falcon 1: m9 <  24357103.63387360446  10 * npr1 â€“ 10 * npr1 â€“ 10 * p1 ab) n1 = 3 np = 20.1 mio Falcon 1: m9 <  3722959.63387360446 â€“ 10 * npr1 â€“ 10 * npr1 â€“ 10 * p1
aa) n1 = 2 np = 13.4 mio Falcon 1: m9 <  24357103.63387360446  20 * npr1 â€“ 10 * p1 ab) n1 = 3 np = 20.1 mio Falcon 1: m9 <  3722959.63387360446 â€“ 20 * npr1 â€“ 10 * p1 Insertion of npr1 results in
aa) n1 = 2 np = 13.4 mio Falcon 1: aaa) m9 <  24357103.63387360446  20 * 0 â€“ 10 * p1 aab) <  24357103.63387360446  20 * 493354.7 â€“ 10 * p1 ab) n1 = 3 np = 20.1 mio Falcon 1: aba) m9 <  3722959.63387360446 â€“ 20 * 0 â€“ 10 * p1 aba) m9 <  3722959.63387360446 â€“ 20 * 493354.7 â€“ 10 * p1
aa) n1 = 2 np = 13.4 mio Falcon 1: aaa) m9 <  24357103.63387360446 â€“ 10 * p1 aab) m9 <  24357103.63387360446  9867094 â€“ 10 * p1 ab) n1 = 3 np = 20.1 mio Falcon 1: aba) m9 <  3722959.63387360446 â€“ 10 * p1 aba) m9 <  3722959.63387360446 â€“ 51135382 â€“ 10 * p1
aa) n1 = 2 np = 13.4 mio Falcon 1: aaa) m9 <  24357103.63387360446 â€“ 10 * p1 aab) m9 <  34224197.63387360446 â€“ 10 * p1 ab) n1 = 3 np = 20.1 mio Falcon 1: aba) m9 <  3722959.63387360446 â€“ 10 * p1 abb) m9 <  54858341.63387360446 â€“ 10 * p1 To get an m9 of 0 in case of making the inequations equations the following results are got:
aa) n1 = 2 np = 13.4 mio Falcon 1: aaa) p1 =  2435710.363387360446 aab) p1 =  3422419.763387360446 ab) n1 = 3 np = 20.1 mio Falcon 1: aba) p1 =  372295.963387360446 abb) p1 =  5485834.163387360446 So m9 = 0 requires a loss of between $ 373,000 and $ 5.5 mio per Falcon 1launch. m9 = 0 is the case where a Merlin (X) requires an investment of $ 2,875,554.2351337147. Are such losses likely? The least one is limited but still would mean a reduction of the capital invested into SpaceX launch by launch of a Falcon 1 â€“ the highest one would mean a quick destruction of SpaceX if there arenâ€™t soon and permanent launches of the other rockets. If a positive m9 is supposed the losses per Falcon 1launch will be higher by up to $ 1,548,141.0574563466 if all of m9, m9h and m5 are supposed to be NOT negative. But the launches all together may sum up to a profit. Under this aspect the losses might be correct. At this point it should be mentioned what the upper boundary of the investment into a Merlin (X) under the assumption that all m9, m9h and m5 are positive results in â€“ an investment into one Falcon 9 Heavy of $ 80,515,518.5837440116 without the aluminium. This is by $ 2.5 mio higher than the launch price of $ 78 mio listed last year. So there is something wrong. The reason may be 1) erroneously applied/inserted wrong number 2) undetected error during modifications 3) too high salaries assumed 4) the application of economical impossibilities 5) improper employee ratios May be that the yet to be calculated alternative sets of numbers will lead to more proper results. The results here also donâ€™t accord to what has been said at the beginning of the previous post â€“ except for the result aba) where the loss per Falcon 1launch is less than $ 400,000 and thus marginal in comparison to the investment into the Merlin (X). Itâ€™s looking a bit as if conclusions to the salaries are possible. On the other hand it might be perhaps that the idea that all margins must be positive really is not correct. In particular it might be that m9 can or will be negative â€“ because then m1 can be positive. This would mean that Falcon 1launches yield a profit. Then the investment into the Merlin (X) would be higher (although invalid here because of something wrong or improper). At an m9 < 0 m9h would be positive. Please refer to tables about links between the margins and links between m9 and X (Merlin) posted earlier. But at present the view is within the equation system which among others is based on Elon Muskâ€™s issue that the present prices do NOT account for reusability although he is out on reusability. This means that a wider view must be applied for a short moment now. The prices donâ€™t account for reusability but the rockets are intended to be reusable. If the reusabilitytechnology works then the prices depreciate the Merlin (X) by one single flight â€“ which means that beginning at the second flight that portion of the price that is caused by notaccountingforreusability really is a revenue. And this revenue may well include a profit! If a margin is negative then it simply must be subtracted from that revenue/profit. Then at the minimum p1 and npr1 close to zero there will be a profit of close to $ 2 mio per Falcon 1launch. Next at that minimum p1 and npr1 below $ 2 mio there still will be a profit per Falcon 1launch. This means that perhaps the first flight only might yield a loss. Another important point also is that the larger npr1 is supposed to be and the larger the refurbishmentportion of this large npr1 (< 2556769.1) is supposed the more this portion is turned into a revenue if the rocket fails and is lost. Of course this does NOT mean a profit â€“ but since it will not be spent for refurbishments in such a case it can be used to finance the replacement of the lost rocket after subtraction of the loss included in the price. This contributes to keeping a positive Cash Flow even in the case of the loss of the rocket. But before looking into details applying the wider view first some critical tasks need to be done within the narrower view â€“ during the thread the following tasks have been listed: Quote: So I consider the manufactureringteam to be the only one growing here. Like I already said earlier I have in mind to apply alternative numbers/values also to check what changes then and by how much it does change. Quote: It also is looking as if the equations are adjusted to the seond version of the launch manifest at present because of applying L2008 for the Falcon 9 â€“ I have to check that. Quote: So after getting results from this L2008 has to be replaced by L2007 in the Falcon 9equation(s) and two alternative results have to be calculated per case â€“ four results to be expected if I havenâ€™t forgotten something. Next additional four results might be got by replacing the L2006 etc. by L2006Q1 etc. â€¦ â€¦ â€¦ Finally it seems to be unclear yet what the relation or function between X and Y is in the calculations done up to now. The Falcon 1equation is Falcon 1: X = 6677536.930521075146 â€“ 0.03625 * 24080486.40  Y + m1 = 5804619.298521075146 â€“ Y + m1 . So itâ€™s clear that the Merlin (X) and the Kestrel (Y) are negatively linked â€“ the higher the investment into the Merlin the smaller that into the Kestrel. The result for the Kestrel (Y) was got from the Cash Flowequation and is Cash Flow: Y < 2556769.1  npr1 . So the profit p1 obviously doesnâ€™t have no impact on the investment into the Kestrel. The maximum investment into it is $ 2,556,769.1 â€“ then the minimum investment into the Merlin (X) is got by inserting the maximum Y: Falcon 1: X = 5804619.298521075146 â€“ 2556769.1 + m1 = 3247850.198521075146 + m1 . At the maximum investment into the Kestrel (Y) npr1 would be 0. Above it turned out that p1 must be a loss and thus negative because of npr1 = 0 p1 = m1 is valid â€“ and the minimum X is higher than the maximum Y. In other words the Kestrel always is a smaller investment than the Merlin â€“ if the current calculations and results are kept including the errors etc. May be that later much more can be seen when better tables are available via Excel. What I didnâ€™t think about yet are npr9, npr9h and npr5. They might be concluded from npr1. I am not sure if the number of engines or the surface or a combination of them would be the best to be applied. It seem to be clear though that the higher npr1 the worse the number of engines as criterion because a builtin loss might be got that never might be counteracted by reusability â€“ I have in mind to so calculations of this but donâ€™t know if I will do them in the next post or later. The question is what needs refurbishment â€“ the engine(s) or the surface. This moment I prefer the surface as criterion. The surfaces of the Falcons are Code: Falcon surface stages ratio to Falcon 1 npri Falcon 1 80.11 1 1 npr1 = 1 * npr1 Falcon 5 531.56 2 6.6 npr5 = 6.6 * npr1 Falcon 9 599.42 2 7.5 npr9 = 7.5 * npr1 Falcon 9 Heavy 1197.70 4 15 npr9h = 15 * npr1 This list seems to add another constraint having an effect on earlier results because of the upper boundary of npr1 â€“ I will consider it later. Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Space Station Commander
Joined: Wed Dec 08, 2004 12:55 pm
Posts: 506 Location: Germany 
Something I forgot to post..
SpaceX updated their homepage with new performance data from Cape Canaveral for Falcon 9, Falcon 9 Heavy. http://www.spacex.com/falcon9.php http://www.spacex.com/falcon9_heavy.php _________________ "The hardest hurdle to space isn't the technicalities and money. But rather, the courage and the will to do it."  Burt Rutan. 
Back to top 

Moderator
Joined: Thu Jun 03, 2004 11:23 am
Posts: 3745 Location: Hamburg, Germany 
Hello, Klaus,
I am working on the Excel spreadsheet already and provide the possibility to insert alternative data. So the data you are linking to can be applied easyly. I up to now apply the data from 2005/2006 but will apply the actual data later I think at present. Regarding my previous post one remark seems to required  the variable nonpropellant costs npr NOT NECESSARYLY are refurbishment costs and if they are really not it should be doubted if the aurface area or the number of engines are proper criterions to conclude from npr1 to npr9, npr9h and npr5. As long as the prices don't account for reusability I am doubting much if the nprs got here include refurbishment costs because the nonaccounting for reusabilty means that a complete replacement of the engines is supposed to apply a pricing that includes selfinsurance. If the engines are NOT lost then the investment into the engines included in the prices is turned into refurbishment costs to any degree. ... Dipl.Volkswirt (bdvb) Augustin (Political Economist) 
Back to top 

Page 3 of 3 
[ 40 posts ] 
Who is online
Users browsing this forum: No registered users and 10 guests 